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發(fā)表于 2014-5-26 23:12:49
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9.2.3 Converting Dimensions to Equal Bilateral Tolerances& O4 P- Y2 A7 c( {! O- R
In Fig. 9-2, there were several dimensions that were toleranced using unilateral tolerances: T+ |1 `( a$ n4 u' n7 m3 E
(such as .375 +.000/-.031, 3.019 +.012/-.000 and .438 +.000/-.015) or unequal bilateral tolerances (such* x! }/ z9 @, b$ G! ~8 k- L
as +1.500 +.010/-.004 ). If we look at the length of the shaft, we see that there are several different ways we$ B% K6 l2 U. ?/ B, s. }
could have applied the tolerances. Fig. 9-4 shows several ways we can dimension and tolerance the length
& U8 t! `$ |: Z) H; Q- oof the shaft to achieve the same upper and lower tolerance limits (3.031/3.019). From a design perspective,
( M" e7 K7 _4 L, ball of these methods perform the same function. They give a boundary within which the dimension is8 j' \ W0 ~! Z3 J# b" w1 ~" U/ `
acceptable.
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3 m% F2 E) I' `! D, f- Y; K. TThe designer might think that changing the nominal dimension has an effect on the assembly. For
& U h3 E* z- D/ o fexample, a designer may dimension the part length as 3.019 +.012/-.000. In doing so, the designer may6 G6 ~7 W: b- u; D+ o, L! E2 b5 _- c
falsely think that this will help minimize the gap for Requirement 1. A drawing, however, doesn’t give' k* n) e+ Q7 U# S$ N5 L* C, c
preference to any dimension within the tolerance range.+ f& h# S% Z1 v+ `% s
Fig. 9-5 shows what happens to the manufacturing yield if the manufacturer “aims” for the dimension
0 b* c/ J+ f3 C2 N' X5 }* g0 V( E- Gstated on the drawing and the process follows the normal distribution. In this example, if the manufacturer
3 G, {. n5 E0 ]# f; C+ Z) `aimed for 3.019, half of the parts would be outside of the tolerance zone. Since manufacturing shops want
- `) k/ ~7 y. o% B, L5 mto maximize the yield of each dimension, they will aim for the nominal that yields the largest number of
8 @; v3 Y, d+ j* N& lgood parts. This helps them minimize their costs. In this example, the manufacturer would aim for 3.025., X$ E* c4 _8 X
This allows them the highest probability of making good parts. If they aimed for 3.019 or 3.031, half of the3 a3 y$ _; h7 c& n6 N
manufactured parts would be outside the tolerance limits." O5 S0 {5 p( i7 q" [3 e( l
As in the previous example, many manufacturing processes are normally distributed. Therefore, if we$ D) H# {1 ~' _8 Q2 K1 A7 m
put any unilateral, or unequal bilateral tolerances on dimensions, the manufacturer would convert them to2 C& B3 I1 {' f9 m5 {
a mean dimension with an equal bilateral tolerance. The steps for converting to an equal bilateral tolerance
! @+ l( E! Q2 `follow." g9 d/ J N9 W, J6 F, R
1 A4 m$ j# _# k- e. u% X
; }' g3 D- [0 h- J2 S6 r$ _1. Convert the dimension with tolerances to an upper limit and a lower limit. (For example, 3.028 +.003/! m7 e/ o) I& I) I7 `: T8 k
-.009 has an upper limit of 3.031 and a lower limit of 3.019.)
) P8 Y+ C% a R5 w0 j& q4 }2. Subtract the lower limit from the upper limit to get the total tolerance band. (3.031-3.019=.012)
# e' ~0 F# r {9 w1 Z/ j% \8 q3. Divide the tolerance band by two to get an equal bilateral tolerance. (.012/2=.006)
! v4 V- z2 f, I4 X+ Q$ g( D# H$ I4 O6 o4. Add the equal bilateral tolerance to the lower limit to get the mean dimension. (3.019 +.006=3.025)., Y) B- n1 ~) M4 B7 J
Alternately, you could subtract the equal bilateral tolerance from the upper limit. (3.031-.006=3.025)2 s" b% V7 r1 ^6 d
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As a rule, designers should use equal bilateral tolerances. Sometimes, using equal bilateral tolerances
~) ~. V4 k- \, W; h9 R% Hmay force manufacturing to use nonstandard tools. In these cases, we should not use equal bilateral1 ]* [5 ]0 z3 ^3 p# e( h
tolerances. For example, we would not want to convert a drilled hole diameter from Æ.125 +.005/-.001 to
0 ]' J; D3 d" U( ^Æ.127 ±.003. In this case, we want the manufacturer to use a standard Æ.125 drill. If the manufacturer sees
. t0 n' p, j( Q) O. z' [Æ.127 on a drawing, he may think he needs to build a special tool. In the case of drilled holes, we would
/ v8 {) ]7 X& d* c+ yalso want to use an unequal bilateral tolerance because the mean of the drilling process is usually larger
! _; p$ X) C2 s; D! Ithan the standard drill size. These dimensions should have a larger plus tolerance than minus tolerance.
% J1 b# S4 i- Q& S, t* ~5 v% N! CAs we will see later, when we convert dimensions to equal bilateral tolerances, we don’t need to keep
8 s- Z9 L$ m9 g* Utrack of which tolerances are “positive” and which tolerances are “negative” because the positive toler-
! E# a6 k4 k# H5 r& b* Qances are equal to the negative tolerances. This makes the analysis easier. Table 9-1 converts the neces-
0 }$ D# G+ M$ O1 a7 W. asary dimensions and tolerances to mean dimensions with equal bilateral tolerances.
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"Dimensioning and Tolerancing Handbook, by Paul J. Drake, Jr."4 V& |+ ?+ d8 k8 [$ q( ?7 q
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