|
本帖最后由 shouce 于 2015-11-26 21:34 編輯
* ~+ u( j, v+ \; a# f- y7 f) B4 |( \
% examlpe7.m. s! A0 b: V. z* o
a=0; b=2;* k3 N% _1 Y& O q2 r# t
eps1=1e-12;eps2=1e-12;9 n) Q! p& ^+ _) s0 h3 p6 [
N=300;
1 J: D# S \2 O$ U5 b, t2 o7 v# EA=[-0.104020146 35.0002164 -0.004160847]; E, m5 I1 s6 o3 H% @: w+ R
[m,n]=size(A);9 _: I' ] R( ?; Q" u9 }; |
for i=1:m
( J5 X6 c& f" pa1=A(i,1);b1=A(i,2);m1=A(i,3);
6 A/ r/ |* Z3 Yend
# q2 f$ S$ e) ~0 h" n! nf=@ (x) ((285+60*tan(45*pi/180)-b1*sin(x)-a1*cos(x))*(a1+b1*m1)+(60)^2*x*(sin(x)-m1*cos(x))-60*285*tan(45*pi/180)*(m1*sin(x)+cos(x)));4 w; q ~4 N# V: g
Hfun=@Bisection;
) [. m; k+ k1 i; P9 T[k,x,f_value]= feval(Hfun, f,a,b,eps1,eps2,N);
3 b% P/ l: `/ B* I( b1 n, e* R8 A
2 ]- O( J, l( [& \1 d7 K
8 S3 d3 v% q) S4 J% A 為離散點(diǎn)坐標(biāo)及導(dǎo)數(shù) 中心距 285 左旋 螺旋角45度 在二分法中增加一部些程序,方便了很多6 I* }- E+ a5 }! t
, p+ y8 f- A4 d/ u2 n部分運(yùn)行結(jié)果:
& _- j4 ?! A& f 35, 1.303240794, 1.303240794, 1.303240794,0.000000896,% U- Y- v# F3 \$ n2 _& F6 J+ C9 W+ X
36, 1.303240794, 1.303240794, 1.303240794,0.000000279,
! ~4 X: a7 s( t 37, 1.303240794, 1.303240794, 1.303240794,-0.000000030,
9 t% f6 u' N; F! _' p" o- f7 m" @ 38, 1.303240794, 1.303240794, 1.303240794,0.000000124,
' L U, B* D2 g, w) U! X% A 39, 1.303240794, 1.303240794, 1.303240794,0.000000047,
5 Y/ M' m0 L4 X! z0 [3 S$ z9 ?2 r 40, 1.303240794, 1.303240794, 1.303240794,0.000000009,' U |3 I/ N3 I8 @+ t, w. m
41, 1.303240794, 1.303240794, 1.303240794,-0.000000011,
" t3 Y, e. t9 \, Z: b u: \
! d5 ?" A5 g/ z" q7 i5 l+ Y5 f# Q3 a) g( | f( |- F9 H
3 X# C, [; l) J) [: S |
|